12-11/k-1/k^2=0

Solution for 12-11/k-1/k^2=0 equation:

D( k )

k^2 = 0

k = 0

k^2 = 0

k^2 = 0

1*k^2 = 0 // : 1

k^2 = 0

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

12-(11/k)-(1/(k^2)) = 0

12-11*k^-1-k^-2 = 0

t_1 = k^-1

12-1*t_1^2-11*t_1^1 = 0

12-t_1^2-11*t_1 = 0

DELTA = (-11)^2-(-1*4*12)

DELTA = 169

DELTA > 0

t_1 = (169^(1/2)+11)/(-1*2) or t_1 = (11-169^(1/2))/(-1*2)

t_1 = -12 or t_1 = 1

t_1 = -12

k^-1+12 = 0

1*k^-1 = -12 // : 1

k^-1 = -12

-1 < 0

1/(k^1) = -12 // * k^1

1 = -12*k^1 // : -12

-1/12 = k^1

k = -1/12

t_1 = 1

k^-1-1 = 0

1*k^-1 = 1 // : 1

k^-1 = 1

-1 < 0

1/(k^1) = 1 // * k^1

1 = 1*k^1 // : 1

1 = k^1

k = 1

k in { -1/12, 1 }